nments: MATH-200 X KCSecure https://smccd.instructure.com/courses/14437/assignme

Question

nments: MATH-200 X KCSecure https://smccd.instructure.com/courses/14437/assignments/161133 Duc in 18 hours, 18 minutcs.DuThu 03 22 2018 7:20 va w tet the folloming elsim (H) at asignificanoe tevel of .02 Ho:87 84.7 11'' : ': 5.9. You obtamsample mean of M-82.4 you believe te populationistocmally astnbated and vou know the standard denata:s for a sample of size a -32 acurate to three decimal plaea) What is the critical vae for thria tet (Repart a critical va What is the teat statisti: for this sampleRepoet answer aceuace to three decimal places) The test staticti: iz in the critical ezion Thas test slatistac leais to a decuan to reect the null ace the all As goch, tte final concaion is that O There is afficient evidence to warrant rejection of the claim that the populaticn mean ia less than s4 There ts xt sullicent evndee to warnnil reecthon ot the clam that the popalaloi t Teple data upport the claim thn the popmltioa mean is less than S4.3 s less thai 84.7 Foin pcsstblc: 5 This is allepl 1 of 3 Qs 1:02 AM 3/22/2018 Type here to search

Explanation / Answer

CRitical value for this test = -2.05
decision is zvalue < -2.05

Test statistics:

z = ( M - mu) /( s/sqrt(n))
= ( 82.4 - 84.7)/(5.9/sqrt(32))
= -2.2052
The test statistic is in the critical region

This test statistic leads to a decision to reject the null hypothesis

As such the final conclusion is that, there is sufficient evidence to warrant rejection of the claim thatthe population mean is less than 84.7

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