his Question: 1 pt 19 of 20 (14 c This Test: 20 pts possib parts a through c PX·

Question

his Question: 1 pt 19 of 20 (14 c This Test: 20 pts possib parts a through c PX·(Round to three decam at place as needed ) O A. As the number of O B. The observed value or the random vanable wa be wss than the mean of the random vanatse ¡ mostobservations O C. The observed value of the random variable wil be equal to the mean of the random vanabie in most observations O D. As the number of observations, n, decreases, the mean of the observations wil approach the mean of the random vanable n, increases, the mean of the observations will approach the mean of the random variable 8 0

Explanation / Answer

From the given data, below table is created

Here in order to find the mean i.e. expected value we take the sum of (x*P(x)) = 1.917

hence xbar = 1.917

interpretation : Option A

Further, we calculate the variance using the formula sum ( (x-xbar)^2*P(x)) which is calculated as 1.6581

std. dev. = sqrt(var) = sqrt(1.6581) = 1.2877

Hence,

mu(x) = 1.917

sigma(x) = 1.288

x P(X = x) x*P(x) (x-xbar)^2*P(x) 0 0.166 0 0.6100 1 0.214 0.214 0.1800 2 0.319 0.638 0.0022 3 0.139 0.417 0.1630 4 0.162 0.648 0.7029

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