1) Write out the formula for calculating the 95% confidence interval for a sampl
ID: 3064879 • Letter: 1
Question
1) Write out the formula for calculating the 95% confidence interval for a sample mean.
2) In this problem, you will compute confidence intervals for the mean under a variety of conditions and compare the results. You will also discuss what accounts for differences in these confidence intervals, if any. Please use Excel to show your work and report your results with two digits to the right of the decimal point.
a) Using =T.INV.2T() and the formula for calculating the confidence interval, calculate the exact 95% confidence interval (upper and lower limits) for the following:
i) n = 40, mean = 32, S.D. = 6
ii) n = 40, mean = 32, S.D. = 12
iii) n = 140, mean = 32, S.D. = 6
iv) n = 140, mean = 32, S.D. = 12
b) Using t = 2 and the formula for calculating the confidence interval, calculate the approximate 95% confidence interval (upper and lower limits) for the following:
i) n = 40, mean = 32, S.D. = 6
ii) n = 40, mean = 32, S.D. = 12
c) Compare the confidence intervals computed in a.i and a.ii, above. What accounts for any differences observed?
d) Compare the confidence intervals computed in a.i and a.iii, above. What accounts for any differences observed?
e) Compare the confidence intervals computed in b.i and b.ii, above. What accounts for any differences observed?
f) Compare the confidence intervals computed in a.i and b.i, above. What accounts for any differences observed?
Explanation / Answer
1)
CI = mean+ / -z * (std.deviation/ sqrt(n))
= mean + - 1.96 * (std.deviation /sqrt(n))
Here, z value for 95% = 1.96
a)
b)
c)
As std.deviation increases confidence interval increases
d)
As sample size increases confidence interval increases
e)
As std.deviation increases confidence interval increases
f)
There is no difference approx slight difference
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