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w.webassign. net/web/Student/Assignment. Responses/submitdep: 181293 16#Q13 E-Res) fazero.com D gotfeefaxcom MYUAlbanyPodium Net UAlbany Mail elp?Read It Notes + PODStat5 6.AE 010 of these manufacture manufacturer and model of the next car purchased at this auto center, and define events Ei, 52, and Ea by E1- simple event because there is more than one model Honda (for example, Civics, Accords, and Insights) er of different manufacturers. Three of these manufacturers are Japanese: Honda, Nissan, and Toyota. Consider the Honda, E2 Nissan, and Es Toyota. Notice that E1 i 6.10 A large auto center sells cars made by a number Suppose that P(Ei) 0.30, P(E2) -0.22, and P(E3) 0.20 Because E1, E2, and E3 are disjoint, the addition rule gives P (Honda or Nissan or Toyota)-P (E, U E2 U Ea) -P(E)+P(B2) +P(Es) 0.30+0.22 +0.20 0.72 What is the probability that the next car purchased is Nissan or Toyota? 0.36 Use the addition rule The probability that the next car purchased is not one of these three types is P(not E or E2 or E)- P (E, UEUE) -1-0.72-0.28 What is the probability that the next car purchased is not Nissan or Toyota? 0.8 Recall that for any event P(E)+P(not E)-1 Let's try to find the probability that the next car purchased is not Honda or Nissan or Toyota in a different way P (ES)-1-P (E) : 07, P (ES) : 0.78, P (E)-0.8 0.7 + 0.78 + 0.8-2.28 > 1 P(El) + P (E) + P (E) What's wrong? There are no mistakes. It doesn't matter what is placed before the decimal point. Only the numbers after the decimal point define the value of the pr (e) This example doesn't concern the addition rule at all. So we can't use this rule here. O We shouldn't add these probabilities. We should multiply them. So P-(0.7) (0.78) (0.8) -0.4368 ENExplanation / Answer
a) P(nissan or toyota)
= P(E2 or E3)
= P(E2) + P(E3)
= 0.22 + 0.20
=0.42
b)
P(not nissan or toyota)
=1 - 0.42
=0.58
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