In order to study the harmful effects of DDT poisoning, the pesticide was fed to

Question

In order to study the harmful effects of DDT poisoning, the pesticide was fed to 6 randomly chosen rats out of a group of 12 rats. The other 6 rats were used as the control group. The following data gives the measurements of the amount of tremor detected in the bodies of each rat after the experiment The more tremor, the more harmful 1 2 3 456 Rat Poisoned Group: 12.2 16.9 25.022.48.520.6 Control Group 11.1 121 9.3 6.6 9.6 82 A computer analysis is done with the output below (the differences are compuled as control- poisoned) t-test Estimate67 3.006 10 00132 std Error2.7002 Lower 95%-14.1331 Upper 95%-2.1003 Difference t-test DF Probs-t (Assuming equal variances.) Which of the following is correct? O groups. The p-value is large. There is good evidence that the two means are different O The p-value is large. There is good evidence that the two sample means dier, in tact, the control group appears to have tewer tremors, on average The confidence interval does not include 0, Hence there is no evidence that the means are the same for both The confidence interval does not include 0. Hence, there is evidence that the mean number of tremors for all potential rats in the poisoned group is larger than that in the control group. O The p-value is small. There is good evidence that the two means are equal.

Explanation / Answer

Option D is Correct Interpretation. Here P value of 0.0132 is not large. So, Option B and C are ruled out

and Option E is wrong Interpretation of small p value, it should be good evidence that two means are different. So, option E is also ruled out

Here Confidence Interval contain 0 and Option D Statement is Correct Interpretation of this interval becaue the interval contain only negative values

Correct option is D

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