5. (2 pts) Event Attend a 4-year college Attend a junior college Attend a techni

Question

5. (2 pts) Event Attend a 4-year college Attend a junior college Attend a technical school Train as an apprentice No formal training after high school Probability 0.1 0.2 0.1 0.1 0.5 At a certain high school, if a student is selected at random and asked what they plan to do after graduating, the probability distribution for their response is given above. Determine the following:

(a) P(Attend a technical school) =

(b) P(Attend a junior college) =

(c) P(Receive training after high school but not at a college) =

6. Choose a student in grades 9 to 12 at random and ask if he or she is studying a language other than English. (You may assume that students are studying at most one language besides English.) Here is the distribution of the students:

(a) What is the probability that a randomly chosen student is, in fact, studying a language other than English?
ANSWER   

(b) What is the probability that a randomly chosen student is studying French, German, or Spanish?
ANSWER   

(c) What is the probability that a randomly chosen student is studying a language besides English, but not German?
ANSWER   

7.Suppose that, for students who are enrolled in college algebra, 79 percent are freshmen, 45 percent are female, and 31 percent are female and are freshmen. Your answers below should be entered as decimals and rounded to three decimal places.

(a) One student will be selected at random. What is the probability that the selected student will be a freshman or female (or both)?

(b) One student will be selected at random. What is the probability that the selected student will not be a freshman?

(c) Two students will be independently selected at random. What is the probability that both of the selected students will be female?

Explanation / Answer

5) probability values are not clear, plz paste it properly!

6)

a) P(Other than english)= P(S)+ P(F) +P(G) + P(All Or's)= 0.24+ 0.09 +0.04+0.01= 0.38

b) P(F) + P( G) + P(S) = 0.09+ 0.04 +0.24= 0.37

c) Probability of besides Englisg but not German= P(S) + P( F) + P(A) = 0.24+ 0.09 + 0.01= 0.34

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