9] A sum greater than or equal to 10. [1 point] 10] A3 on one die or on both dic
ID: 3064293 • Letter: 9
Question
9] A sum greater than or equal to 10. [1 point] 10] A3 on one die or on both dice. [1 point] 11] Standing in line at a movie theater are 10 How many ways are there of arranging these people? [1 point) There are 16 distinct crayons in a box. people (so order matters), and one couple is ins 12] How many ways are there of arranging those 16 crayons? [1 point] 13] 6 crayons will be used to create color PINs. How many PINs can be created? [1 po 14] 6 crayons are placed in a bag. How many ways to choose 6 crayons are there? [1 The following doctors were available on staff in a hospital Choose one doctor at random. Find the following probabilities: MD Doctor of Osteopathy Pathology6 Pediatrics 7 38 Orthopedics 20 15] She is a pathologist? [1 point] 16] He is an orthopedist or an MD? [1 point] heet GE RULEDExplanation / Answer
11. Given there are 10 people and there is one couple in it which can be grouped as one unit. So, the number of ways of arranging these people = (10-1)! = 9! = 362880.
12. Number of ways of arranging 16 distinct crayons = 16!
13. If 6 distinct crayons are used to create color pins, number of pins that are created = 16*15*14*13*12*11 = 5765760. This is because, the first colour can be any one from the set of 16 crayons. The second color should be different fro first one, so there are 15 possibilities to pick second crayon and the same logic applies for the rest of the places.
14. Number of ways of choosing 6 crayons = 16C6 = (16*15*14*13*12*11)/(6*5**3*2*1) = 8008.
15. P(pathologist) = (6+1)/(6+1+7+2+20+2) = 7/38 = 0.1842
16. P(orthopedist or MD) = P(orthopedist)+P(MD)-P(othopedist and MD) = (22/38)+(33/38)-(20/38) = 35/38 = 0.921
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