eworkid-4646031948iquestionld-6&flushed-false;&cld-4834543;&centerwin-yes; MAT-1

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eworkid-4646031948iquestionld-6&flushed-false;&cld-4834543;&centerwin-yes; MAT-152-LIN (LC 2018SP) Homework: Test 2 Practice (Old Test Questions-Not for Grade score: 0 of 1 pt 6 of 17 (8 complete) Instructor-created question An urn contains 10 marbles: 4 Blue. 3 Gold, 2 Black, 1 White. 3 draws will be made, one-at-a-time. without replacment All answers should be entered as simplified fractions or decimal numbers (rounded to 2 decimal places). 1) Find the probability that the 1st draw Black 2) Find the probability that the "3rd draw Blue" 3) Find the probability that the "1st draw Gold and 3rd draw Blue 4) Find the probability that the-1st draw white or 2nd draw white or 3rd draw white" 5) Find the probability that the "1st draw blue and 2nd draw black and 3rd draw gold 6) Find the probabity that the "1st draw gold or 2nd draw gold or 3rd draw gold. Hint the complement rule is an easier calculation) Enter your answer in the edit fields and then click Check Answer Clear All All parts showing

Explanation / Answer

1. Probability of first draw black = 2/10 = 1/5 = 0.2

2. Probability that that the '3rd draw black' = P(not blue,not blue,blue) + P(not blue,blue,blue) + P(blue,blue,blue)

(6/10)(5/9)(4/8) + (6/10)(4/9)(3/9) + (4/10)(3/9)(2/8) = 216/720

=3/10 = 0.3

3. probability that the '1st draw gold and 3rd draw blue' =

P(gold,gold,blue) + P(gold,black,blue) + P(gold,blue,blue) + P(gold,white,blue)

= (3*2*4)/720 +(3*2*4)/720 + (3*4*3)/720 + (3*1*4)/720

= 2/15 = 0.133

4.Probability that '1st draw white or 2nd draw white or 3rd draw white' = 1 - P(not white,not white,not white)

= 1 - 7/10 = 3/10 = 0.3

5.Probability that the '1st draw blue and 2nd draw black and 3rd draw gold' = (4*2*3)/720 = 1/30 = 0.033

6.Probability that the'1st draw gold or 2nd draw gold or 3rd white' = 1 - P(not gold,not gold,not gold)

= 1- (7*6*5)/720 = 7/24 = 0.291

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