Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

9:54 1 webassign.net 3. -12 points JKEStat11 5.E.054. My Notes Suppose that you

ID: 3063725 • Letter: 9

Question

9:54 1 webassign.net 3. -12 points JKEStat11 5.E.054. My Notes Suppose that you are in a class of 32 students and it is assumed that approximately 17% of the population is left-handed. (Give your answers correct to three decimal places.) (a) Compute the probability that exactly five students are left-handed. (b) Compute the probability that at most four students are left-handed. (c) Compute the probability that at least six students are left-handed. Need Help? RedTk odter Submit Answer Save Progress Practice Another Version

Explanation / Answer

Given

n=32

p=0.17 therefore q=1-0.17=0.83

a)

r=5

We have to find

P(X=r)=nCr *p^r*q^(n-r)

=32C5* 0.17^5 * 0.83^(32-5)

=0.18679

b)

Atmost 4

P(X<4)=P(X=<3)

=P(X=0)+P(X=1)+P(X=2)+P(X=3)

==32C0* 0.17^0 * 0.83^(32-0)+=32C1* 0.17^1 * 0.83^(32-`1)+=32C2* 0.17^2 * 0.83^(32-2)+=32C3* 0.17^3* 0.83^(32-3)=0.182656

c)

Atleast 6

P(X>6)=1-P(X<=6)

P(X<=6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)

=0.70447

Hence 1-0.70447=0.29553