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____ 3.- Based ONLY on the SPSS output below, at the 5% significance level, we c

ID: 3063112 • Letter: #

Question

____ 3.- Based ONLY on the SPSS output below, at the 5% significance level, we can conclude:

Tests of Between-Subjects Effects

Dependent Variable:   RecyHouseDay

Source

Type III Sum of Squares

df

Mean Square

F

Sig.

Corrected Model

.442a

11

.040

1.090

.370

Intercept

2975.417

1

2975.417

80668.574

.000

Neighborhood

.216

2

.108

2.930

.055

Season

.095

3

.032

.856

.464

Neighborhood * Season

.129

6

.022

.584

.743

Error

8.225

223

.037

Total

2987.525

235

Corrected Total

8.667

234

a. R Squared = .051 (Adjusted R Squared = .004)

1. There is an effect of neighborhood on the mean weight of materials recycled per day per household in the population because Sig. =0.055.

2. There is no evidence of an effect of neighborhood on the mean weight of materials recycled per day per household in the population because Sig. =0.055.

3. There is an effect of neighborhood on the mean weight of materials recycled per day per household in the sample because Sig. =0.055.

4. There is no evidence of an effect of neighborhood on the mean weight of materials recycled per day per household in the sample because Sig. =0.055.

Tests of Between-Subjects Effects

Dependent Variable:   RecyHouseDay

Source

Type III Sum of Squares

df

Mean Square

F

Sig.

Corrected Model

.442a

11

.040

1.090

.370

Intercept

2975.417

1

2975.417

80668.574

.000

Neighborhood

.216

2

.108

2.930

.055

Season

.095

3

.032

.856

.464

Neighborhood * Season

.129

6

.022

.584

.743

Error

8.225

223

.037

Total

2987.525

235

Corrected Total

8.667

234

a. R Squared = .051 (Adjusted R Squared = .004)

Explanation / Answer

Answer to the question is as follows:

Actual alpha = .05

Since actual alpha = .05 which is smaller than .055, we say that

" There is no evidence of an effect of neighborhood on the mean weights of materials reccycled per day per household in the population because sig = .055"

Option 2 is correct. Please remember that in ANOVA we use sample statistics to assess the likelihood that the hypothesis on the entire popualtion is true