A small hair salon in Denver, Colorado, averages about 35 customers on weekdays

Question

A small hair salon in Denver, Colorado, averages about 35 customers on weekdays with a standard deviation of 11. It is safe to assume that the underlying distribution is normal. In an attempt to increase the number of weekday customers, the manager offers a $3 discount on 5 consecutive weekdays. She reports that her strategy has worked since the sample mean of customers during this 5 weekday period jumps to 45. Use Table 1.

What is the probability to get a sample average of 45 or more customers if the manager had not offered the discount? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)

A small hair salon in Denver, Colorado, averages about 35 customers on weekdays with a standard deviation of 11. It is safe to assume that the underlying distribution is normal. In an attempt to increase the number of weekday customers, the manager offers a $3 discount on 5 consecutive weekdays. She reports that her strategy has worked since the sample mean of customers during this 5 weekday period jumps to 45. Use Table 1.

Explanation / Answer

( please revert for any clarification)

for normal distribution z score =(X-)/ here mean=       = 35 std deviation   == 11.00000 sample size       =n= 5 std error=x=/n= 4.9193

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