ppose the repair time for an air rage repair time of 90 minutes and a standard d

Question

ppose the repair time for an air rage repair time of 90 minutes and a standard deviation of to min e next air conditioning unit unit folows a normal probability distribution with a standard deviation of 10 minutes Let Y be the repair brme a. What is the probability that the repair time will take more than 75 minutes? (s points) What is the probability the repair time will take between 80 and 100 minutes? (5 points) at is the probability the repair time will take more than 105 minutes? (5 points)

Explanation / Answer

1)

z value at 75 minutes

Z = (X - ) /
Z = (75 - 90) / 10

Z = -1.5

P-vaqlue at z=-1.5

P(X>75)= 0.9332

2)

z score at 80

Z = (X - ) /
Z = (80 - 90) / 10

Z = -1

z value at x=100

Z = (X - ) /
Z = (100 - 90) / 10

Z = 1

P(80<x<100) = 0.6827

3)

z value at x=105

Z = (X - ) /
Z = (105 - 90) / 10

Z = 1.5

P(X>105)= 0.0668

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