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m) interpret the findings. n) construct an ANOVA summary table O) Caclulate w2 a

ID: 3061881 • Letter: M

Question

m) interpret the findings.

n) construct an ANOVA summary table

O) Caclulate w2 and interpret

P) conduct protected t tests if necessary

study guide

192 2. A researcher is interested in the effect of emotion on concentration. He designs a two-sample study in which anger is induced in one sample by having a confederate provoke arn argument in the lab waiting room. The control group does not undergo this mood induction. Both samples are then tested on a computer stunt driving game, where a joystick is used to maneuver a car around a track, avoiding crashes with obstacles. The number of errors of each subject is given below. Angry Group Control Group 13 6 9 7 10 Conduct a one-way ANOVA on these data (even though there are only two levels of the independent variable) Compare your conclusions to Chapter 8, problem 3, in which this same study was analyzed using an independent-samples t test. a. state Ho and H,. b. Calculate ss c. Calculate Ssy- d. Calculate Ss. e. Calculate df,G f. calculate df g. Calculate df, h. Calculate MSBg i. Calculate MSv. j. Co k. What is Ecrit fo Reject Ho? mpute the E ratio

Explanation / Answer

Step 1

Null Hypothesis Ho : µ1 =µ2

Alternative Hypothesis : µ1 µ2

Step 2

Degrees of freedom between = k - 1 = 2 - 1 = 1

Degrees of freedom Within = n - k = 12 - 2 = 10

Degrees of freedom Total F( k-1,n - k,) at 0.05 is = F Crit = 4.965

Step 3

Grand Mean = G / N = 9+6.833 / 2 = 7.917

SST = ( Xi - GrandMean)^2 = (6-7.917)^2 + (9-7.917)^2 + (13-7.917)^2 + ……..& so on = 70.917

SS Within = (Xi - Mean of Xi ) ^2 =,(6-9)^2 + (9-9)^2 + (13-9)^2 + ……..& so on = 56.833

SS Between = SST - SS Within = 70.917 - 56.833 = 14.084

Step 4

Mean Square Between = SS Between / df Between = 14.084/1 = 14.084

Mean Square Within = SS Within / df Within = 56.833/10 = 5.683

Step 5

F Cal = MS Between / Ms Within = 14.084/5.683 = 2.478

We got |F cal| = 2.478 & |F Crit| =4.965

MAKE DECISION

Hence Value of |F cal| < |F Crit|and Here We Accept Ho

Treatments ONE WAY ANOVA Mean = X /n Angry Group 6 9 13 11 5 10 9 Contro Group 6 5 8 6 9 7 6.833