Questions 1-2: A certain bag of m&m;\'s contains 8 red, 6 green, 4 orange, 5 yel
ID: 3061728 • Letter: Q
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Questions 1-2: A certain bag of m&m;'s contains 8 red, 6 green, 4 orange, 5 yellow, 12 brown, 3 blue and 2 pink m&m;'s. One m&m; is chosen at random from the bag. 1. What is the probability of the chosen m&m; being red or green? (a) 25% (b) 30% (c) 3596 (d) 40% 2. What is the probability of the chosen mêm being neither brown nor orange? n Questions 3.4 Suppose the chance of rain is 70 % on Friday and 10 % on Saturday. Assume that the two events, "rain on Friday' and "rain on Saturday' are independent. What is the chance of rain on both Friday and Saturday? (a) 7% What is the chance of rain on Friday or Saturday (or both)? (a) 80% 3. Saturday? (b) 12% (d) 40% (c) 1596 4. (b) 73% (c) 68% (d) 65% Questions 5-6: The following table shows the frequencies of various hair colors and eye colors within a certain group of women. Blue l Brown l Green Hair Eyes Blonde Brunette Red-Head 10 35 30 10 5 One woman is selected at random from the group. 5. What is the probability of the selected woman being a brunette or green-eyed? (a) (b) (c) (d) What is the conditional probability of the selected woman having green eyes, given that she is a brunette? (a) ¼ 6. How many different ways are there to choose from a ten member club a governing body consisting of a President, a Vice President, and a Secretary? (a) 1,000 7. (b) 120 (c) 30 (d) 720 How many different ways are there to choose a combination of 3 different women and 5 different men from a group of 6 women and 10 men? (a) 2,100 8. (b) 5,040 (c) 272 (d) 12,870 9. How many different ways are there to permute the letters in the word 'terrier? (d) 1,260 (b) 420 (c) 630 (a) 140Explanation / Answer
1) P(red or green) = 8/40 + 6/40 = 0.35 = 35%
2) P(neither brown nor orange) = 1 - P(brown or orange)
= 1 - (12/40 + 4/40)
= 1 - 16/40 = 24/40 = 3/5
3) P(both friday and saturday) = 0.7 * 0.1 = 0.07 = 7%
4) P(friday or saturday or both ) = 0.7 * 0.9 + 0.1 * 0.3 + 0.7 * 0.1 = 0.73 = 73%
5) Total women = 120
P(brunette or greeneyed) = 70/120 + 50/120 - 30/120 = 90/120 = 3/4
6) P(green| brunette) = 30/70 = 3/7
7) No of ways = 10 * 9 * 8 = 720
8) No of ways = 6C3 * 10C5 = 5040
9) No of ways = 7!/(2! * 3!) = 420
7!
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