nmng with a smal sample of 7 anoriy sei led consumers or pietopars a through bra
ID: 3061603 • Letter: N
Question
nmng with a smal sample of 7 anoriy sei led consumers or pietopars a through brand name has a 60% reco iton rate. Assume the owner of he brand wantsto ve fy th t rate by b a. What is the probability that exactly 6 ot the selected consumers recogrize the brand name? The probablity that exactily 6 of the 7 consumers recognize the brand name is Round to three decimal places as needed.) b. What is the probability that all of the selected consumers recognize the brand name The probability that anoftascieded consumers recogize te brand name is Round to three decimal places as needed) c. What is the probability that at least 6 of the selected consumers recognize the brand name? The probablity that at least 6 of the selected consumers recognize the brand name is (Round to three decimal places as needed d. W 7 consumers are randomly selected, is 6 an unusually high number of consumers that recognize the brand name Yes, because to probably tat 6 or more ofthe selected consumers recogno the brand name is loss than 005 B. . bo ano the abity that 6 or more of the seedod onsumers reoorwo he brand name .s gealer than 005 O C. Yos, because the probablity that 6 or more of the selected consumers recognibe the brand name s greafor than 0 05 OA.Explanation / Answer
Ans:
Use Binomial distirbution with n=7,p=0.6
P(x=k)=7Ck*0.6k*(1-0.6)7-k
a)P(x=6)=7C6*0.66*0.41=0.131
b)P(x=7)=0.67=0.028
c)P(x>=6)=P(x=6)+P(x=7)=0.131+0.028=0.159
d)Option B is correct.(No,as P(x>=6)>0.05,so not unusual)
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