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The President of an auto dealership believes there is a relationship between the

ID: 3061185 • Letter: T

Question

The President of an auto dealership believes there is a relationship between the number of new cars sold and the number of sales people on duty. To investigate, he selects a sample of 8 weeks and observes the number of cars sold and the number of sales people on duty for that week as follows:

1.Compute a 95% interval for mean car sales for weeks when 9 sales people are on duty.

2.In checking the work schedules for next week, the President finds that there are 9 sales people scheduled to be on duty. Develop a 95% interval for the number of cars sold next week.

Week

Sales Staff

Cars Sold

1

5

53

2

5

47

3

7

48

4

4

50

5

10

58

6

12

62

7

3

45

8

11

60

Week

Sales Staff

Cars Sold

1

5

53

2

5

47

3

7

48

4

4

50

5

10

58

6

12

62

7

3

45

8

11

60

Explanation / Answer

Let xi = number of Sales Staff in the ith week and yi = number of Cars Sold in the ith week.

Back-up theory in brief

The linear regression model Y = 0 + 1X + , ………………………………………..(1)

where is the error term, which is assumed to be Normally distributed with mean 0 and variance 2.

Estimated Regression of Y on X is given by: Y = 0cap + 1capX, ………………………….(2)

where

1cap = Sxy/Sxx and 0cap = Ybar – 1cap.Xbar..……………………………………………..(3)

Mean X = Xbar = (1/n)sum of xi ………………………………………….……………….(4)

Mean Y = Ybar = (1/n)sum of yi ………………………………………….……………….(5)

Sxx = sum of (xi – Xbar)2 …………………………………………………..………………………………..(6)

Syy = sum of (yi – Ybar)2 …………………………………………………..………………………………..(7)

Sxy = sum of {(xi – Xbar)(yi – Ybar)} …………………………………………………………………….………(8)

All above sums are over i = 1, 2, …., n

n = sample size ………………………………………………………………………………(9)

Estimate of 2 is given by s2 = (Syy – 1cap2Sxx)/(n - 2)…………………………………..(10)

100(1 - )% Confidence Interval (CI) for ycap at x = x0 is                                                                                              (0cap + 1capx0) ± tn – 2, /2xs[(1/n) + {(x0 – Xbar)2/Sxx}]…………………………………(11)

100(1 - )% Prediction Interval (PI) for ycap at x = x0 is                                                                                              (0cap + 1capx0) ± {tn – 2, /2 x s[1 + (1/n) + {(x0 – Xbar)2/Sxx}]}…………………………(12)

Preparatory Work

Summary of Excel Calculations

n

8

xbar

7

ybar

52.875

Sxx

82.875

Syy

288.875

Sxy

141.125

1cap

1.70286576

0cap

40.7420814

s^2

8.09301156

Part (a)

95% interval for mean car sales for weeks when 9 sales people are on duty

= 95% confidence interval for ycap at x = 9

CIYcapLB

53.22

CIYcapUB

58.92 [vide (11) above]ANSWER

Part (b)

95% interval for the number of cars sold next week.

= 95% Prediction Interval (PI) for ycap at x = 9

=

PI LB

48.55

PIUB

63.59 ANSWER

[vide (12) above]

DONE

n

8

xbar

7

ybar

52.875

Sxx

82.875

Syy

288.875

Sxy

141.125

1cap

1.70286576

0cap

40.7420814

s^2

8.09301156

Part (a)

95% interval for mean car sales for weeks when 9 sales people are on duty

= 95% confidence interval for ycap at x = 9

CIYcapLB

53.22

CIYcapUB

58.92 [vide (11) above]ANSWER

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