Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

w History Bookmarks People Window Help Do Homework - krysten Mossburg ecure http

ID: 3060940 • Letter: W

Question

w History Bookmarks People Window Help Do Homework - krysten Mossburg ecure https://www.mat d com Student PlayorHomework.aspx?homeworkId=471442717&questionId;=11&flushed-false;&cid-4913354; STAT 216-801, Spring 2018 Homework: Ch5 Score: 0 of 1 pt 5.3.28-T krysten Mossburg 3/12/18 110122(21 complete) Hw Score: 95.45%, 21 Question He Find a value of the standard normal random variable z, call it zo, such that the following probabilities are satisfed a.Plzs%)-00421 e. P-20 $2s0)-0.2685 E P(-3 2)-0.9644 h. PIzS20)-0.0035 a -rRound to two decimal places as needed ) Unter your answer in the answer box and then click Check Answer 7 penaning MacBook Air 2 3 4

Explanation / Answer

a)

P(z<z0) = 0.0421

So, z0 =-1.73   (using z table)

b)

P(-z0 <z<z0) =0.99

So P(z<-z0) +P(z>z0) =1-0.99

2P(z>z0) =0.01

P(z>z0) =0.005

P(z<z0) =1-0.005 =0.995

So, z0 =2.58

c)

P(-z0 <z<z0) =0.90

So P(z<-z0) +P(z>z0) =1-0.90

2P(z>z0) =0.10

P(z>z0) =0.05

P(z<z0) =1-0.05 =0.95

So, z0 =1.64

d)

P(-z0<z<z0) =0.8402

So P(z<-z0) +P(z>z0) =1-0.8402

2P(z>z0) =0.1598

P(z>z0) =0.0799

P(z<z0) =1-0.0799 = 0.9201

So,z0 =1.41