ata Analysis T/R> Assessment Due in 1 hours, 17 minutes. Due Sun 03/11/2018 11:5

Question

ata Analysis T/R> Assessment Due in 1 hours, 17 minutes. Due Sun 03/11/2018 11:59 p Show Intro/Instructior Assume that a sample is used to estimate a population mean Find the margin of aror ME that corresponds to a sample of size 16 with a mean of 152 and a standard deviation of 13.5 at a confidence level of 99 9% Report ME accurate to one decimal place because the sample statistics are presented with this accuracy Answer should be obtained without any preliminary rounding However, the critical value may be rounded to 3 decimal places Get help: Video Points possible: 2 This is attempt 1 of 3. Post this question to forum Submit 8 9 6 7

Explanation / Answer

t value at 99.9% = 4.073 (critical value using standard table)
s = 13.5 , n = 16

ME = +/- t * (s/sqrt(n))
= +/-4.073 * (13.5/sqrt(16))
= +/-13.7

Hence ME = 13.7

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