1. ANSWER PART B PLEASE 2. A-C ABOVE PLEASE Refer to the table below. Given that
ID: 3060198 • Letter: 1
Question
1.
ANSWER PART B PLEASE
2.
A-C ABOVE PLEASE
Refer to the table below. Given that 2 of the 214 subjects are randomly selected, complete parts (a) and (b). Group AB 13 17 20 64 13 Type 13 a. Assume that the selections are made with replacement. What is the probability that the 2 selected subjects are both group B and type Rh*? 0.,0063 (Round to four decimal places as needed.) b. Assume the selections are made without replacement. What is the probability that the 2 selected subjects are both group B and type Rh* (Round to four decimal places as needed.)Explanation / Answer
2) SInce the selection are made without replacement, we will first select one subject from both group B and type Rh+. This can be done with the probability = no of subject in group B with type Rh+/ total number of subjects = 17/214
Now, we have total number of subject = 213 and no. of subjects in group B with type Rh+ = 16 since selection is made without replacement. Thus, the probability of selecting second subject with same group and type = 16/214
Total probability = 16*17/214*213 = 0.00596 , approx = 0.006
2) Since company hires employees on Mondays, Tuesdays or Wednesdays with equal likelihood, the probability of hiring on any one of these days = 1/3
a) If two different employees are randomly selected, the probability that they were both hired on Wednesday = (1/3)*(1/3) = 1/9
part b) and c) are not in the image of the question provided. Thanks!
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.