Ls4202_endsem_2017 please answer only question no.4. (5 marks) LS4202: Biostatis
ID: 3060011 • Letter: L
Question
Ls4202_endsem_2017
please answer only question no.4. (5 marks)
Explanation / Answer
Answer
Terminology
The following gives a brief explanation of various terms and short form used in presenting the answer.
Estimated Regression of Y on X is given by: Y = 0cap + 1capX, ………………………….(2)
where
1cap = Sxy/Sxx and 0cap = Ybar – 1cap.Xbar..……………………………………………..(3)
Mean X = Xbar = (1/n)sum of xi ………………………………………….……………….(4)
Mean Y = Ybar = (1/n)sum of yi ………………………………………….……………….(5)
Sxx = sum of (xi – Xbar)2 …………………………………………………..………………………………..(6)
Syy = sum of (yi – Ybar)2 …………………………………………………..………………………………..(7)
Sxy = sum of {(xi – Xbar)(yi – Ybar)} …………………………………………………………………….………(8)
All above sums are over i = 1, 2, …., n, n = sample size ……………………………………(9)
Estimate of 2 is given by s2 = (Syy – 1cap2Sxx)/(n - 2)…………………………………..(10)
Standard Error of 1cap is sb, where sb2 = s2/Sxx …………………………………………(11)
Standard Error of 0cap is sa, where sa2 = sb2{(sum of xi2 over i = 1, 2, …., n)/n}……… (12)
Now, to answer Q4
Typical null hypothesis to test if the assumed regression model is effective to predict y based on x:
H0: 1= 0 Vs HA: 1 0.
Test statistic is: t = 1cap/SE(1cap) [vide (11) above]
Crititcal value is upper (/2)% point of tn – 2
Null hypothesis is rejected at level of significance % if |tcal| > critical value. DONE 1
100(1 - )% Confidence Interval (CI) for 1 = 1cap ± {SE(1cap) x tn – 2, /2} DONE 2
100(1 - )% Confidence Interval (CI) for 0 = 0cap ± {SE(0cap) x tn – 2, /2} DONE 3
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