(7 pts) 3. The temperatures, in degrees Celsius, of frozen dinners in a refriger

Question

(7 pts) 3. The temperatures, in degrees Celsius, of frozen dinners in a refrigerated truck have a standard normal distribution. If a frozen dinner is selected at random from the truck, find the probability that it is between 08°C and 1.34°C. Use the chart. time it takes mice to run through a maze is normally distributed with a mean of 22.5 seconds and a standard deviation of 3.8 seconds. 4. The (7 pts) a. Find the probability that a randomly selected mouse will take over 30 seconds to run through the maze. Use the chart. (6 pts) b. Find the probability that a randomly selected mouse will run through the maze in under 10 seconds. Use your calculator, and record the command used. maze in less time. Use the chart. 7 pts) d. If 10 mice run through the maze, find the probability that their mean time to complete the maze is over 25 seconds. You may use your calculator

Explanation / Answer

Ans:

3)

P(-0.08<z<1.34)=P(z<1.34)-P(z<-0.08)

=0.9099-0.4681=0.4418

4)Given that

mean=22.5

standard deviation=3.8

a)

z=(30-22.5)/3.8=1.974

P(z>1.974)=1-P(z<=1.974)=1-0.9758=0.0242

b)

z=(10-22.5)/3.8=-3.29

P(z<-3.29)=0.0005

c)P(Z<=z)=0.9

z=1.282

cut off time=22.5+1.282*3.8=27.37

d)standard error of mean=3.8/sqrt(10)

z=(25-22.5)*sqrt(10)/3.8=2.08

P(z>2.08)=1-P(z<=2.08)=0.0187

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