Syllabus-BA 2300-180 × \\. Cengage x / Mindlap-Cengage Lea x \\ e Chegg Study |
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Syllabus-BA 2300-180 × . Cengage x / Mindlap-Cengage Lea x e Chegg Study | Guided S: X New Tab Not secure ngcengage.com/static/nb/ui/index.html?nbId=740021&nbNodeld;:279396983&eISBN;:9781 3371153774|&parentld;:279397314 d : Apps D Bootyquak Bookmarks D Point Reduction and The ideal growing cc D CAKE BIRTH Shroomery PF TEK Shroomery-casing D How to Legally Acce Other bookmark MINDTAP James lyons- Chapter 6 Assignment Due on Mar 19 at 11-59 PM EDT Questions Exercse 06.39 Question 9 of 10 Check My Work 8 9. eBook 10.The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of a wedding is $29,858 (Xo Group website, January 5 , 2015). Assume that the cost of a wedding is normally distributed with a mean of $29,858 and a standard deviation of $5,600 a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)? 0.0392 b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)? 0.4715 C. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number? 39070 Hide Feedback Correct Check My Work Icon Key 7:00 PM ^41)3/9/2018 Type here to searchExplanation / Answer
a) P(X < 20000)
= P((X - mean)/sd < (20000 - mean)/sd)
= P(Z < (20000 - 29858)/5600)
= P(Z < -1.76)
= 0.0392
b) P(20000 < X < 30000)
= P((20000 - mean)/sd < (X - mean)/sd < (30000 - mean)/sd)
= P((20000 - 29858)/5600 < Z < (30000 - 29858)/5600)
= P(-1.76 < Z < 0.03)
= P(Z < 0.03) - P(Z < -1.76)
= 0.5120 - 0.0392
= 0.4728
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