Let x be a random variable that represents white blood cell count per cubic mial
ID: 3057063 • Letter: L
Question
Let x be a random variable that represents white blood cell count per cubic mialiliter of deviation 1650. A test result of x 3500 is an indication of leukoeria. This inda." boe iume ders whoe blood. Assume that x has a distribution that is approximately normal, with mean u 6050 and estimated standar thi (a) What is the probability that, on a single test, x is less than 35007 (Round your answer to four decima places.) a doctor uses the average for two tests taken about a week apart. What can me say about the probability about a week apart. What can we say about the probability dstribution of ution of x is approximately normal with 6050 and o - 1166.73 The probability distribution of x is not normal The probablity distribution of x is approximately normal with- The probability distribution of x is approximately normal with -6050 and -1650. -825.00. " 6050 and what is the probability of-Explanation / Answer
a)
=6050
=1650
z=(x-)/
=(3500-6050)/1650
=-2550/1650
=-1.55
P(x<3500) =P(z<-1.55) =0.0606
b)
x==6050
x =/n =1650/2 =1166.73
so its choice A
z=(x-)/x
=(3500-6050)/1166.73
=-2550/1166.73
=-2.19
P(x<3500) =P(z<-2.19) =0.0143
c)
x =/n =1650/3 =952.6279
z=(x-)/x
=(3500-6050)/1166.73
=-2550/952.6279
=-2.68
P(x<3500) =P(z<-2.68) =0.0037
d)
the probability decreased as n increased
It would be an extremely rare event for a person to have two or three tests below 3,500 purely by chance,The person probably does not have leukopenia
so choice D
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