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Moving to another question will save this response. « | Question 19 of 26 > » Question 19 0.04 points Save Answer The batteries produced in a manufacturing plant have a mean time to failure of 1,754 months, with a standard deviation of 5 months. I select a simple random sample of 71 batteries produced in the manufacturing plant. What is the standard deviation of the sampling distribution of the mean time to failure for the 71 batteries? Moving to another question will save this response. Question 19 of 26

Explanation / Answer

19)

std deviation of sampling mean =std deviation/(n)1/2 =5/(71)1/2 =0.5934

20)

from abvoe populatin std deviation =1.023

S.No X (X-xbar) (X-xbar)2 1 9.10 1.200 1.4400 2 8.00 0.100 0.0100 3 6.60 -1.300 1.6900 x 23.7 3.1400 xbar=x/n 7.900 s2=(x-xbar)2/(n)= 1.0467 s=s2                            = 1.023

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