I did a, b, and c but I can\'t figure out d. A set of final examination grades i

Question

I did a, b, and c but I can't figure out d.

A set of final examination grades in an introductory statistics course is normally distributed, with a mean of 77 and a standard deviation of 8. Complete parts (a) through (d) a. What is the probability that a student scored below 91 on this exam? The probability that a student scored below 91 is 0.9599 Round to four decimal places as needed.) b. What is the probability that a student scored between 69 and 991? The probability that a student scored between 69 and 99 is 0.8383 (Round to four decimal places as needed.) C. The probability is 5% that a student taking the test scores higher than what grade? The probability is 5% that a student taking the test scores higher than 90 Round to the nearest integer as needed.) d if the professor grades on a curve for example, the professor could give A s to the top 10% of the class, regardless of the score , is a student better off with a grade of 93 on this exam or a grade of 66 on a different exam, where the mean is 62 and the standard deviation is 4? Show your answer statistically and explain. A student is with a grade of 93 on this exam because the Z value for the grade of 93isand the Z value for the grade of 66 is (Round to two decimal places as needed.)

Explanation / Answer

z score for a grade of 93 = (93 - 77)/8 = 16/8 = 2

z score for a grade of 66 in different exam = (66 - 62)/4 = 1

Hence,

A student is better with a grade of 93 on this exam because Z value for the grade of 93 is 2 and the Z value for the grade of 66 is 1.

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