ot binomial try not binomi Exploratory Exercises State th e odds of an event occ
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ot binomial try not binomi Exploratory Exercises State th e odds of an event occurring given the probability that it occurs as follows. 1 to 1 2. 3 to 1 3. 1 to 6 5. 7 to 8 15 16 5 to 3 State th e probability of an event occurring given the following odds. 18 19 o 4's 9. 10. 12. 7 10 11 16 Solve each of the following. are 6-to-l against an event oc- curring. What is the probability that it 14. The probability of an event occurring is 8. What are the odds that it will not occur? 1 to 3 heads will occur? ility Written Exercises In a baa the probability of each of the following selections. 5 1. all 3 pennies 2. all 3 nickels 5. 1 penny, 1 dime, 1 nickel 1 3. all 3 dimes 6. 1 dime, 2 nickels 4. 2 pennies, 1 dime ,6 56 In a bag are 5 red, 9 blue, and 6 white marbles. Two are selected at random. Find the probability of each of the following selections. 7. 2 red 8. 2 blue 9. 1 red and 1 blue ? 10. 1 red and 1 white 19 95 There are 5 fudgesicles and 8 popsicles in the freezer. If 2 are selected at random, find the probability of each of the following. 11. 2 fudgesicles 39 12. 2 popsicles Suppose you select 2 letters from the word dlgebra. What is the probability of selecting 2 letters and having the following occur? 13. I vowel and 1 consonant - 14. 2 vowels 15. 2 consonants 7 Sharon has 8 mystery books and 9 science fiction books. Four are selected. Find the probability of each of the following. 16. 4 mystery books 18. 2 mysteries and 2 science fiction 38 17. 4 science fiction books 170 19. 3 mysteries and 1 science fiction 18 85 85 rom a deck of 52 cards, 5 cards are dealt. What are the odds of the following? .5 aces 21. 5 face cards 33 to 108,25722. 5 from one suit 3310 1Explanation / Answer
Answer to #3)
7 pennies , 4 nickels and 5 dimes
Total = n = 7+4+5 = 16
P(all 3 dimes) = number of ways of selecting dimes / total number of ways of selecting any three coins
Number of ways of selecting 3 dimes out of 5 = 5C3
Number of ways of selecting any three coins out of 16 = 16C3
P(all three dimes) = 5C3 /16C3
P(all three dimes) = 10 / 560
P(all three dimes) = 1/56
.
Answer to #4)
2 pennies and 1 dime
Number of ways of selecting 2 pennies = 7C2 = 7*6/2 = 21
Number of ways of selecting 1 dime = 5C1 = 5
Total number of ways of selecting 3 coins = 16C3 = 16 *15 * 14 / (3*2) = 560
.
P(2 pennies and 1 dime) = 21 * 5 / 560
P(2 pennies and 1 dime) = 3/16
.
Answer to #5)
Number of ways of selecting 1 nickel = 4C1 = 4
Number of ways of selecting 1 penny = 7C1 = 7
Number of ways of selecting 1 dime = 5C1 = 5
Total number of ways of selecting 3 coins = 16C3 = 560
P(1 dime, 1 nickel and 1 penny) = (4 * 7 * 5) / 560
P(1 dime, 1 nickel and 1 penny) = ¼
.
Answer to #6)
1 dime and 2 nickels
Number of ways of selecting 2 nickels = 4C2 = 4*3/2 = 6
Number of ways of selecting 1 dime = 5C1 = 5
Total number of ways of selecting 3 coins = 16C3 = 560
P(1 dime and 2 nickels) = 6 * 5 / 560
P(1 dime and 2 nickels) = 3/56
.
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