4. 1/3 points | Previous Answers PriviteraStats3 9.E.021 My Notes Ask Your Teach
ID: 3053303 • Letter: 4
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4. 1/3 points | Previous Answers PriviteraStats3 9.E.021 My Notes Ask Your Teacher To demonstrate flavor aversion learning (that is, learning to dislike a flavor that is associated with becoming sick), researchers gave one group of laboratory rats an injection of lithium chloride immediately following consumption of saccharin-flavored water. Lithium chloride makes rats feel sick. A second control group was not made sick after drinking the flavored water. The next day, both groups were allowed to drink saccharin-flavored water. The amounts consumed (in milliliters) for both groups during this test are given below. Amount Consumed by Rats That W Made Sick (n 4) Amount Consumed by Control Rats n 4 ere 8 8 12 (a) Test whether or not consumption of saccharin-flavored water differed between groups using a 0.05 level of significance. State the value of the test statistic. (Round your answer to three decimal places.) 3.425X State the decision to retain or reject the null hypothesis. O Retain the null hypothesis. Reject the null hypothesis (b) Compute effect size using eta-squared (n2). (Round your answer to two decimal places.) n2 2.015Explanation / Answer
2)
a)
mean_diff= -0.52
sd_diff= 0.228
n= 5
t= (mean_diff)/(sd_diff/sqrt(n))
t= -0.52/(0.228035085019827/sqrt(5))
t= -5.099
alpha= 0.05
t(a,n-1) =t(0.05,5-1) =abs(F.INV(0.05,5-1)) = 2.132
p-value= P(T<|t|)
=P(T<(-5.09901951359279)
=T.DIST(-5.09901951359279,5-1,TRUE)
=0.003493687
Since (t=5.099, p<0.05), I reject Ho
b)
r^2 = t^2/(t^2+df)
= (-5.099)^2/(-5.099^2+4)
= 0.86666578
= 0.8667
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