Quiz: Quiz 7 Time Remaining: 02.04.34 Subnit O is Question: 1 pt 8 of 12 (0 comp
ID: 3053103 • Letter: Q
Question
Quiz: Quiz 7 Time Remaining: 02.04.34 Subnit O is Question: 1 pt 8 of 12 (0 complete) This Quiz: 12 pts possit In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with garlic in a processed tablet form measured before and after the treatment. The changes (before- after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4 4 and a standard deviation o 18 9 Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol aner the garlic treatm ent what does the confidence interval suggest about the eftectiveness of garlic in reducing LDL cholesterol? Click here to view at Click here to view page 1 of the standard normal distribution table Click here to levels were table. what is the confidence interval estimate of the population mean ?? (Round to two decimal places as needed) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits do not contain o, suggesting that the gartic treatment did not affect the LDL cholesterot levels O B. The confidence interval limits contain 0, suggesting that the garlic treatment did afect the LDL cholesterol ees O C. The confidence interval limits do not contain 0, suggesting that the garlic treatment did affect the LDL cholesterol levels Click to select your answer(s)Explanation / Answer
Solution:-
8) Given that n = 44 , mean = 4.4 , sd = 18.9
df = n-1 = 44-1 = 43
t = 1.68
sM = ?(18.9^2/44) = 2.85
? = M ± t(sM)
? = 4.4 ± 1.68*2.85
? = 4.4 ± 4.79
-0.39, 9.19
=> -0.39 mg/dL < ? < 9.19 mg/dL
=> option B.
9) For 99% confidence, the z- score is 2.576, E = 0.006,? = 1.25
N = (z * ?/E)^2 = (2.576 * 1.25/0.006)^2 = 288011.111 = 288012
=> option B. No,because the required sample size is a fairly large number.
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