Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

1 points | Previous Accura ng a an drticle, 1.2% a Internet stuLks hat entered h

ID: 3052921 • Letter: 1

Question

1 points | Previous Accura ng a an drticle, 1.2% a Internet stuLks hat entered he merket iri 999 ended up rading below their init al u ttr in pr ILes. Ir you were an rivestar who purchased uur Internet slo s dl lher init.l u ?nny prlLes, what was probatlity that at lenst tw af the wuld end up tradirig at car ahove thrir initial offering pru yaur ariswur dcm plares.) Submit Answer Save PrssPractice Another Version Mty Notes Ask Your leacher In a large on te ob training program, half of the participants are e male ? d half are male. In a random sample of three participants, what is the probabl ity that an investigator will draw at least one male?T Round your ans er to our decim places.) F(x2 1)- 12. 0/1 points | Previous Amewers WarneFMAC6 8.2.028 My Notes Ask Your Teuche tn a largc on the job training program, half of the participants arc fcmalc and half are male. In a random samplc of five participants, what is the probabi ity that an investigator will draw at lcast two males?t (Round your answer to four decimal places.) Need Help? Talk to Tutor

Explanation / Answer

P(X = x) = nCx * px * (1 - p)n - x

a) p = 0.112

n = 4

P(X > 2) = P(X = 2) + P(X = 3) + P(X = 4)

              = 4C2 * (0.112)^2 * (1 - 0.112)^2 + 4C3 * (0.112)^3 * (1 - 0.112)^1 + 4C4 * (0.112)^4 * (1 - 0.112)^0

              = 0.0645

b) P(male) = 0.5

n = 3

P(X > 1) = 1 - P(X < 1)

              = 1 - P(X = 0)

              = 1 - 3C0 * (0.5)^0 * (0.5)^3

              = 1 - 0.125 = 0.875

c) n = 5

p = 0.5

P(X > 2) = 1 - P(X < 2)

               = 1 - (P(X = 0) + P(X = 1))

               = 1 - (5C0 * (0.5)^0 * (0.5)^5 + 5C1 * (0.5)^1 * (0.5)^4)

               = 1 - 0.1875 = 0.8125