solve asap please 12 110] Do government employees take longer coffee breaks than

Question

solve asap please

12 110] Do government employees take longer coffee breaks than pro examine tsmple workers? That is a question that interested a management consand another ranbey spent 1n 10) L issue, he t private sector examine the another random sample en private sector workers and measured the amount of time of t coffee breaks during the day. The results are listed below. t consultant. (in minutes) they spent in Government Employees Private-Sector Wor 23 18 34 31 28 kers 25 19 18 28 25 21 21 25 27 32 21 20 16 present sufficient evidence to indicate a difference in mean time for coffee breaks between the two populations? Test using 0.05. Do the data

Explanation / Answer

Given that,
mean(x)=27.2
standard deviation , s.d1=5.4119
number(n1)=10
y(mean)=21.5
standard deviation, s.d2 =3.6286
number(n2)=10
null, Ho: u1 = u2
alternate, H1: u1 != u2
level of significance, = 0.05
from standard normal table, two tailed t /2 =2.262
since our test is two-tailed
reject Ho, if to < -2.262 OR if to > 2.262
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =27.2-21.5/sqrt((29.28866/10)+(13.16674/10))
to =2.7664
| to | =2.7664
critical value
the value of |t | with min (n1-1, n2-1) i.e 9 d.f is 2.262
we got |to| = 2.76636 & | t | = 2.262
make decision
hence value of | to | > | t | and here we reject Ho
p-value: two tailed ( double the one tail ) - Ha : ( p != 2.7664 ) = 0.022
hence value of p0.05 > 0.022,here we reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 != u2
test statistic: 2.7664
critical value: -2.262 , 2.262
decision: reject Ho
p-value: 0.022

we claim that there is a significance diffrence between the two population mean
values

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