(06.05 LC) At a large university, 20% of a random sample of male students have a
ID: 3052038 • Letter: #
Question
(06.05 LC) At a large university, 20% of a random sample of male students have an overall grade point average (GPA) of 3.5 or higher. A random sample of female student records found that 25% had a GPA of 3.5 or higher. The president of the university wants to determine whether there is evidence of a difference in grades between males and females. What would she write as the null and alternative hypotheses for this situation? (4 points) O Ho:p1-P2-0 and Ha:P1-P2 # 0 Ho:P1 P2 0 and Ha:p1 P2>0 Ho:p1-P2 = 0 and Ha: p1-p2 0 and Ha:P1-P2 = 0 Ho: p2>0 and Ha:pp20Explanation / Answer
5) z = 0.93
P-value = 2 * P(Z > 0.93)
= 2 * (1 - P(Z < 0.93))
= 2 * (1 - 0.8238)
= 2 * 0.1762
= 0.3524
4) At alpha = 0.05, the critical value is z0.025 = +/- 1.96
As z = 2.2 doesn't lie between the critical values, so it is significance
At alpha = 0.01, the critical value is z0.005 = +/- 2.58
As z = 2.2 lies between the critical values (-2.58 < 2.2 < 2.58) so it is not significance.
Option - B is the correct answer.
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