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This Question: 1 pt 1 of 11 This n a recent poi 802 duts were asked to identity

ID: 3051728 • Letter: T

Question

This Question: 1 pt 1 of 11 This n a recent poi 802 duts were asked to identity their tavoxite seat when they ty, and 486 of them chose a window seat Use a o.05 signiicance evlo st the caim that the majnity of d tr indow seals wh y ty ienialy he nul typo which oflheblowing the hypotesis test to be conducted H, p.05 H paos Hps H, p0S What is the les stasic? Round to o alpaces as needed) Whait is the conclusion aboul the nul hypotesis? &Raject; the nul hypothesis because the P.value is greater than the significance levela C. Fail w reject the null typothesis because the P.alue is less than or equal to the sincance level, s the tinal conclusion? Thene is not sufficent evidence to support the claim that the majorty of aduts prefer window seats when they y There in suficiet evidence to warrnt rejection of the claim thail the majotity of aduits preer window seats when they y D. There s nosucent evidence to wamant rejection of the claim that the maity of duts preerwwts when they y Type here to search Dil Prtsen Home Und

Explanation / Answer

n= 802 ,X= 496

p= 496/802= 0.618

a) Null hypothesis H0: P= 0.5

Alternative Hypothesis HA:P >0.5

Q= 1-P= 1-0.5= 0.5

Z= p-P/sqrt(PQ/n)

Z= 0.618-0.5/sqrt(0.5*0.5/802)

Z= 0.118/sqrt(0.000312)

Z= 0.118/0.01766

Z=6.68

The P-Value is 0.00001 The result is significant at p < 0.05.

Reject the null hypothesis because the P value is less than or equal to the significance level alpha

There is sufficient evidence to support the claim that the majority of adults prefer window seat when they fly.

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