This Question: 1 pt This Test 6 pts pos araneropl bo develop . model of wine as
ID: 3051595 • Letter: T
Question
This Question: 1 pt This Test 6 pts pos araneropl bo develop . model of wine as hadged by wne experts data on alcohol content and qal, was colected from variants of a particular wine From sample 12-·-was osatsngts percentages of alcohol to predict wine quality For those data, SSR 21.763 and SST 31,443 Use this infcemation te complete parts (o) through (e) bele a. Determin·the coomcient of determination?, and interpret its meaning r2 .(Round to three decimal places as needed ) interpret the meaning of? "means that%ofthe variation in Round to one decimal place as Y can be explained by the variarion in b. Determine the standard error of the estimate s,x-O(Round to four decimal places as needed ) e. How useful do you think this regression model is for predicting wine quality? O A. It is not very useful for predicting wine qualty because the coefficient of determination is close to 1 O B. It is very useful for predicting wine quality because the coefficient of deterninaton is close to 1 O C. it is not very useful for predicting wine quality because the coefficient of determination is chse to 0 D. It is very useful for predicting wine quality because the coefficient of determination is close to 0 Click to select your answers) J. Type here to searchExplanation / Answer
SolutionA:
R sq=SSR/SST
=21.763/31.443
R^2 =0.692
y---WINE QUALITY
X=% of alcohol
it means that 69.2% variation in wine quality can be explained by variation in percentage of alcohol
Solutionc:
SST=SSR+SSE
given
31.443=21.763+SSE
SSE=31.443-21.763
=9.68
Standard error of estimate
Syx=Sqrt(SSE/n-2)
=sqrt(9.68/12-2)
=0.9838699
=0.9839
STANDARD ERROR OF ESTIMATE=0.9839
ANSWER:0.9839
IT IS USEFUL FOR PREDICTING WINE QUALITY BECAUSE THE COEFFICIENT OF DETERMINATION IS CLOSE TO 1
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