SHOW WORK TO GET FULL CREDIT This problem has 2 independent parts a) and b) Prob

Question

SHOW WORK TO GET FULL CREDIT This problem has 2 independent parts a) and b) Problem 3) a) A researcher receives 106 containers of oxygen. Of those containers, twenty of them have oxygen that is not ionized and the rest are ionized. Two samples are randomly selected, without replacement, from the lot. ) What is the probability that the second one selected is not ionized given that the first one was ionized? (7 Edit. points) Organ Erhan Protea Fill & S Prepare Send fo i) What is the probability that both are not ionized? (7 points) Store and she

Explanation / Answer

106 containers, 20 non-ionized so 86 ionized

i) P(the second is not ionized given the first one was ionized)

= 20/105 = 0.1905=19.05%

ii) P(both are ionized)

= P(the first one selected is ionized) X P(the second is ionized given the first one was ionized)

= (86/106) X (85/105) = 0.638X 0.8095=0.007637

Hope this will be helpful. Thanks and God Bless you :-)

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