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Many studies have suggested that there is a link between exercise and healthy bo

ID: 3051381 • Letter: M

Question

Many studies have suggested that there is a link between exercise and healthy bones. Exercise stresses the bones and this causes them to get stronger. One study examined the effect of jumping on the bone density of growing rats. There were three treatments: a control with no jumping, a low-jump condition (the jump height was 30 centimeters), and a high-jump condition (60 centimeters). After 8 weeks of 10 jumps per day, 5 days per week, the bone density of the rats (expressed in mg/cm3 ) was measured. Here are the data. data5.dat


(b) Run the analysis of variance. Report the F statistic with its degrees of freedom and P-value. What do you conclude? (Round your test statistic to two decimal places and your P-value to three decimal places.)

Conclusion: There is  ---Select---  no a statistically significant difference between the three treatment means at the = .05 level.

Group n s Control Low jump High jump

Explanation / Answer

Descriptive Statistics: Density

Total
Variable Group Count Mean SE Mean StDev
Density Control 1 9 590.78 7.77 23.30
Highjum 3 10 604.90 3.73 11.79
Lowjump2 10 628.90 6.67 21.09

ANOVA :

One-way ANOVA: Density versus Group

Source DF SS MS F P
Group 2 7115 3558 9.64 0.001
Error 26 9599 369
Total 28 16715

S = 19.21 R-Sq = 42.57% R-Sq(adj) = 38.15%


Individual 95% CIs For Mean Based on
Pooled StDev
Level N Mean StDev ---------+---------+---------+---------+
Control 1 9 590.78 23.30 (-------*-------)
Highjum 3 10 604.90 11.79 (-------*-------)
Lowjump2 10 628.90 21.09 (-------*-------)
---------+---------+---------+---------+
592 608 624 640

Pooled StDev = 19.21

Conclusion:P-value < 0.05 we reject the nukll hypothesis we conclude that There a statistically significant difference between the three treatment means at the = .05 level.

Hope this will be helpful. Thanks and God Bless you :-)

F =9.64 P =0.001
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