1. A researcher has a total of 30 employees who were selected from six different
ID: 3050061 • Letter: 1
Question
1. A researcher has a total of 30 employees who were selected from six different departments. There were five employees from each department. The employees were tested and scored on their knowledge of the firm's organizational structure. The researcher conducted an ANOVA to test whether there were differences between the workers' knowledge among the departments. The sum of squares among the groups was 2790. The total sum of squares was 9990.
a. (6 points) Based on the information given, fill in the ANOVA table below.
b. (2 points) Using a 5% level of significance, what is the critical value of F, FCRIT?
c. (1 point) Can the researcher reject the null hypothesis?
d. (1 point) Is there sufficient evidence to say that there is a difference in employees' knowledge of the firm's structure?
Source of Variation
Sum of Squares
d.f.
Mean Squares
FSTAT
Among
Within
Total
S2Y=
Source of Variation
Sum of Squares
d.f.
Mean Squares
FSTAT
Among
Within
Total
S2Y=
Explanation / Answer
rom given information SST =9990 ; SS(among) =2790
hence SS(within) =SST-SS(among) =9990-2790=7200
here df (among) =departmetns -1= 6-1 =5
df(within) =(departments*(5-1) =24
MS(among)=SSamong/df(among) =558
MS(within)=SS(within)/df(among) =300
Fstat =MS(among)/MS(within) =1.86
b) fr 5,24 degree of freedom and 0.05 level critical value =2.621
c) No as test stat is lower than critical value
d) we do not have sufficient evidence to say that there is a difference in employees' knowledge of the firm's structure
source SS df MS Fstat among 2790 5 558 1.86 within 7200 24 300 total 9990 29Related Questions
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