O -2 points DevoreStat9 4 E 050 2 My Notes Ask Your Teache In response to concer

Question

O -2 points DevoreStat9 4 E 050 2 My Notes Ask Your Teache In response to concerns about nutritional contents of fast foods, McDonald's has announced that it will use a new cooking oil for its french fries that will decrease substantially trans fatty acid levels and increase the amount of more beneficial polyunsaturated fat. The company claims that 97 out of 100 people cannot detect a difference in taste between the new and old oils. Assuming that this figure is correct (as a long-run proportion), what is the approximate probability that in a random sample of 1000 individuals who have purchased fries at McDonald's (a) At least 45 can taste the difference between the two oils? (Round your answer to four decimal places.) (b) At most 5% can taste the difference between the two oils? (Round your answer to four decimal places.) You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help? Read ItTalk to a Tutor Submit Answer Save Progress Practice Another Version

Explanation / Answer

Solution:-

P(Not detecct) = 97/100 = 0.97

P(Detect) = 0.03

a) The probability that atleast 45 can taste the difference between the two oils is

p = 0.03

n = 1000

x = 45

By applying binomial distribution:-

P(x, n) =nCxpx*(1-p)(n-x)

P(x > 45) = 0.0056

b) The probability that atmost 5% can taste the difference between the two oils is 0.99976.

p = 0.03

n = 1000

x = 5% = 0.05 × 1000 = 50

By applying binomial distribution:-

P(x, n) = nCxpx*(1-p)(n-x)

P(x < 50) = 0.99976

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