a P.E. teacher is trying to develop a program to improve runs the mile. Over the

Question

a P.E. teacher is trying to develop a program to improve runs the mile. Over the course of the quarter, McWilliams run an extra 2 laps each day. Assuming that the population is 95 minutes ( = 1 minute) and the are normally distributed, what would be McWilliams' null-hypothesis? requires her class to (national) mean time for running the mile 8.3 What is McWilliams' alternative-hypothesis? 8.4 At the beginning of the year, Coach McWilliams' 16 students run the mile in an average of time of 9.8 minutes. Are her students' times "expected" if we are using an alpha level of 05 for our decision-making criteria? SHOW WORK 8.5 At the end of the quarter after completing the training program, Coach McWilliams' 16 students run the mile in an average time of 9.2 minutes. Using an = .05, what decision will you make as a result of the hypothesis test?

Explanation / Answer

Null Hypothesis: H0: mu = 9.5
alternate hypo: H1: mu not equals 9.5

At the begining of year,
Test statistics, t = (9.8 - 9.5)/(1/sqrt(16)) = 1.2

p-value = 0.2487 (use p-value calculator for df = 15)

As p-value is greater than 0.05, we fail to reject null hypothesis.
This menas that there are not significant evidence to conclude that students are not running at expected times.

8.5. At the end of the quarter
Test statistics, t = (9.2 - 9.5)/(1/sqrt(16)) = -1.2

p-value = 0.2487 (use p-value calculator for df = 15)

As p-value is greater than 0.05, we fail to reject null hypothesis.
This menas that there are not significant evidence to conclude that students are not running at expected times.

However we see there is decrease in time after training but as per hypothesis test there are no evidence to conclude that it is not different from population.

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