Create an individual value plot of your data. Does there appear to be an optimal
ID: 3048819 • Letter: C
Question
Create an individual value plot of your data. Does there appear to be an optimal shape and weight for distance of flight (use minitab) Many factors will influence the distance a paper airplane will fly. Weight and shape are two factors. Through this project we will attempt to determine the optimal shape and weight for distance. We will also compare regression and ANOVA to better understand key differences between the methods. In your data, you have four groups and the groups will probably have different means. We will use ANOVA and regression to test whether these differences are statistically significant. The ANOVA model for this project is: y,,-+ a, +6,, fr i= 1,2,3,4 and j=1,2,3,4,5 where E,-N(0,2) It's possible that the 4 means will lie on a line. If so, a test that the slope is zero (Ho : A = 0 ) will also test for a difference in the four means. A linear regression model may also be appropriate: + For the data you collected n = 20 because you did 5 trials with each of 4 different models. HB 4. HB 48 7.ST HB HBExplanation / Answer
ANOVA
Back-up Theory
With the terminology already given in the question,
Null hypothesis: H0: 1 = 2 = 3 = 4 = 0 Vs Alternative: HA: H0 is false, i.e., at least one of the i’s is different from others.
Now, to work out the solution,
Terminology:
Row total = yi.= sum over j of yij
Grand total = G = sum over i of yi.
Correction Factor = C = G2/N, where N = total number of observations = sum of ni’s
Total Sum of Squares: SST = (sum over i,j of yij2) – C
Group Sum of Squares: SSR = {sum over i of (yi.2/ni)} – C
Error Sum of Squares: SSE = SST – SSR
Degrees of Freedom (DF): for SST – total number of observations – 1; for SSR – number of rows – 1; for SSE – (DF for SST - DF for SSR)
Mean Sum of Squares = Sum of squares/Degrees of Freedom
Fcrit: upper % point of F-Distribution with degrees of freedom n1 and n2, where n1 is the DF for SSR and n2 is the DF for SSE
Significance: Fobs is significant if Fobs > Fcrit
ANOVA TABLE
Source of
Variation
Degrees of Freedom (DF)
Sum of squares (SS)
Mean Sum
of squares
(MS = SS/DF)
Fobs
Fcrit*
Significance**
Group
r - 1
SSR
MSR/MSE
Error
N - rr
SSE
Total
N - 1
SST
NOTE:
* Fcrit: upper % point of F-Distribution with degrees of freedom n1 and n2, where n1
is the DF for Row and n2 is the DF for Error
** Significance: Fobs is significant if Fobs > Fcrit
Summary Excel Calculations
NOTE: Question says 4 groups of 5 values each. But, actual values given add to 22. The data is taken as given and analysis is based on 22 values
j
LP
HP
LD
HD
1
11.1
12.7
5.3
8.9
2
7.4
9.3
12.1
4.8
3
8.1
10.2
9.1
7.2
4
7.5
9.1
9.5
9.8
5
9.1
9.1
8.0
8.1
6
10.0
13.7
alpha
0.05
#treat
4
n1
6
n4
6
n2
5
n3
5
n
22
y1.
53.2
y4.
52.5
y2.
50.4
y3.
44
G = y..
200.1
C
1820
Sy1j^2
482.64
Sy4j^2
503.43
Sy2j^2
517.44
Sy3j^2
411.56
Syij^2
1915.07
Syi.^2/ni
1826.31
SST
95.0695
SSR
6.31321
SSE
88.7563
ANOVA TABLE
Source
DF
SS
MS
F
Fcrit
p-value
Activity
3
6.3132
2.104404
0.426778
3.159908
0.73621
Error
18
88.756
4.930907
Total
21
95.07
4.527121
Decision
Since Fcal < Fcrti, null hypothesis is accepted.
=> there is not enough evidence to suggest that the means of the different groups are different.
DONE
Source of
Variation
Degrees of Freedom (DF)
Sum of squares (SS)
Mean Sum
of squares
(MS = SS/DF)
Fobs
Fcrit*
Significance**
Group
r - 1
SSR
MSR/MSE
Error
N - rr
SSE
Total
N - 1
SST
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