Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then

Question

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question Listed below are the weights in pounds of 11 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that sport's league? 186 233 262 252 235 308 300 206 235 260 300 a. Find the mean The mean is pound(s) (Type an integer or a decimal rounded to one decimal place as needed.) b. Find the median. The median is pound(s) (Type an integer or a decimal rounded to one decimal place as needed.) c. Find the mode Select the correct choice below and, if necessary, fill in the answer box to complete your choice 0 A. The mode(s) is(are) pound(s). Type an integer or a decimal. Do not round. Use a comma to separate answers as needed.) O B. There is no mode d. Find the midrange The midrange is pound(s) (Type an integer or a decimal rounded to one decimal place as needed.) e. Are the results likely to be representative of all players in that sport's league? ( A. The results are likely to be representative because a championship team is most likely representative of the entire league ( B. The results are not likely to be representative because the median is not equal to the mean ° C. The results are not likely to be representative because the median is not equal to the mode 0 D. The results are not likely to be representative because the championship team may not be representative of the entire league

Explanation / Answer

The statistical software output for this problem is:

Summary statistics:

Hence,

a) Mean = 252.5

b) Median = 252

c) Modes = 235, 300

d) Midrange = (Min + Max)/2 = (186 + 308)/2 = 247

e) Option D is correct.

Column Mean Median Mode Min Max Data 252.45455 252 Multiple modes 186 308

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.