° 2. A data set includes 103 body temperatures of healthy adult humans having a
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Question
° 2. A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1F and a standard deviation of 0.56F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view a t distribution table.1 Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.3 ° What is the confidence interval estimate of the population mean ? Round to three decimal places as needed.) What does this suggest about the use of 98.6°F as the mean body temperature? O A. This suggests that the mean body temperature could be higher than 98.6°F O B. This suggests that the mean body temperature could be lower than 98.6°F ° C. This suggests that the mean body temperature could very possibly be 98.6°FExplanation / Answer
(a)
n = 103
x-bar = 98.1
s = 0.56
% = 99
Standard Error, SE = s/n = 0.56/103 = 0.05517844
Degrees of freedom = n - 1 = 103 -1 = 102
t- score = 2.624891469
Width of the confidence interval = t * SE = 2.62489146850733 * 0.0551784395772004 = 0.144837415
Lower Limit of the confidence interval = x-bar - width = 98.1 - 0.144837415291741 = 97.95516258
Upper Limit of the confidence interval = x-bar + width = 98.1 + 0.144837415291741 = 98.24483742
The 99% confidence interval is [97.955, 98.245]
(b) Option (B)
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