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Let z be a random variable with a standard normal distribution. Find the indicat

ID: 3047559 • Letter: L

Question

Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.)

P(0.93 z 0)=

Find z such that 81% of the standard normal curve lies to the left of z. (Round your answer to two decimal places.)
z =

Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)

= 39; = 16

P(50 x 70) = Please show me how to solve rather than just providing an answer, and how a graph would look like for all the problems

Explanation / Answer

Solution :

Using standard normal table ,

P(0.93 z 0) = P(z 0) - P(z -0.93) = 0.5 - 0.1762 = 0.3238

P(0.93 z 0) = 0.5 - 0.1762

P(0.93 z 0) = 0.3238

Probability = 0.3238

The z such that 81% of the standard normal curve lies to the left of z is ,

P(Z < z) = 81%

P(Z < z) = 0.81

P(Z < 0.88) = 0.81

z = 0.88