Score: 0 of 1 pt 320141(22 complete) HW Score: 56%, 28 of 50 pt 5.3.41 Question

Question

Score: 0 of 1 pt 320141(22 complete) HW Score: 56%, 28 of 50 pt 5.3.41 Question Help * A mechanic sells a brand of automobile tire that has a life expectancy miles. He wants to give a guarantee for free replacement of tires that don't wear well. h that is normally distributed, with a mean life of 30,000 miles and a standard deviation of 2600 How should he word his guarantee if he is willing to replace approximately1 the tires? Tires that wear out bymiles will be replaced free of charge Round to the nearest mile as needed )

Explanation / Answer

here for 10 percentile ; crtiical value of z =1.2816

therefore corresponding value =mean +z*std deviation =30000-1.2816*2600 =26668

(Note : some times they use nly two places after decimal for z ; then use 26672 if above does not work and revert)

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