.11 Sprint 17%) 11:35 PM canvas.csun.edu CSUN D Question 12 1 pts For a randomly

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.11 Sprint 17%) 11:35 PM canvas.csun.edu CSUN D Question 12 1 pts For a randomly selected family with three children, what's the probability of Boy-50%. PlGi0-50%) P(three girls) ? D Question 13 1 pts For a randomly selected family with three children, what's the probability of PB0j: 50%. PlGii)-50%): Probability of getting either 3 girls or 3 boys? D Question 14 1 pts For a randomly selected family with three children, what's the probability of Boy-50%, PlGil)-50%) Probability of getting neither three boys nor three girls? D Question 15 1 pts People can only have one of 4 different blood types in the population: A, B, AB, or O. The

Explanation / Answer

Question 12

Pr(Three girls) 1/2 * 1/2 * 1/2= 1/8 = 0.125

Question 13

Pr(Either 3 girls or 3 boys) = Pr(3 girls) + Pr(3 boys) = 1/2 * 1/2 * 1/2 + 1/2 * 1/2 * 1/2 = 1/8 + 1/8 = 2/8 = 0.25

Question 14

Pr(Neither 3 boys nor 3 boys) = 1 - Pr(Either 3 boys or 3 girls) = 1 - 1/2 = 1/2 = 0.5

Question 15

Pr(O or A or B) = Pr(O) + Pr(A) + Pr(B) = 0.44 + 0.41 + 0.10 = 0.95

Question 16

Pr(Neither O nor A nor B) = 1 - Pr(O or A or B) = 1 - 0.95 = 0.05

Question 17

Pr(O an A blood type) = As these events are mutually exclusive = 0

Question 18

Pr(Two people of A blood type) = 0.41 * 0.41 = 0.1681

Question 19

Pr(One person with A blood type and one person with B blos type) = 2 * Pr(A) * Pr(B) = 2 * 0.41 * 0.10 = 0.082

Question 20

Pr(One person with B blood type l A blood group person is alreaday selected) = Pr(B l A) = Pr(B) = 0.10

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