Airlines often sell more tickets on a flight than there are available seats .. t

Question

Airlines often sell more tickets on a flight than there are available seats .. the airline company has 180 seats . The no show probability is relatively low at 5%. The binomial distribution can describe this situation . - If the airline sells 185 tickets what is the probability that there will be an overbooking situation ? - if the airline sells 200 tickets what is the probability of having empty seats ? - if the airline wants only 2% probability of an overbooking situation , how many tickets should it sell ? Airlines often sell more tickets on a flight than there are available seats .. the airline company has 180 seats . The no show probability is relatively low at 5%. The binomial distribution can describe this situation . - If the airline sells 185 tickets what is the probability that there will be an overbooking situation ? - if the airline sells 200 tickets what is the probability of having empty seats ? - if the airline wants only 2% probability of an overbooking situation , how many tickets should it sell ? - If the airline sells 185 tickets what is the probability that there will be an overbooking situation ? - if the airline sells 200 tickets what is the probability of having empty seats ? - if the airline wants only 2% probability of an overbooking situation , how many tickets should it sell ?

Explanation / Answer

The independent probability of a passenger arriving for a booked flight is 0.95.

p=0.95

X= no. of passengers arrived.

X follows binomial disribution.

P[X=x] = nCx px (1-p)n-x

P[ X >=181 ] = 0.04325728381

P[X <180 ] = 0.00115990825

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