o. At 298 K, the value of Ke for the reaction H: (g)+Br(g) 2HBr (g) is a. 4.0x 1
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o. At 298 K, the value of Ke for the reaction H: (g)+Br(g) 2HBr (g) is a. 4.0x 10-38 b. 5.0 x 10- ?. 1.0 1019 d. -2.0x 10 19 e. 2.2 x 10-10 1 10. For the second-order reaction A products, 0.189 concentration of A is 0.489 M, how long would it take for A to be 20.9% consumed? . If the initial a. 1.24sb. 286s c. 41.0s d. 8.28s e10.8s 11. Which of the following is not a postulate of collision theory? a. Reactant molecules must collide to react. b. Reactant molecules must collide with a certain minimum energy to form products. c. Reactant molecules must collide with the correct orientation to form products d. The rate constant is directly proportional to the energy of activation. c. The maximum in the potential energy curve, the activati by the structure of the activated complex or transition state. 12. For the formation of l mol of nitrosyl chloride at a given temperature, ? -44 kJ N?(g) + ½ Cl2 (g) NOCl(g) The activation energy for this reaction is 59 kJ/mol. What is the activation energy for the forward reaction? a. 59 kJ/mol b. 15 kJ/molc. 103 kJ/mol d.-44 kJ/mol e.-103 kJ 13. The rate constants for the first-order decomposition of a compound are 6.19 x 10s at 43°C and 2.71 x 10s at 65°C. What is the value of the activation energy for this reaction? (R-831 J/(mol-K)) a. 0.677 kJ/mol b. 25.9 kJ/mol c. 0.558 kJ/mol d. 59.6 kJ/mol e. 1.56 kJ/mol 14. Which substance involves no attractive forces except London-dispersion forces? a. Cao (s) b. C, (ag) c. N2 6) d. H:O) e. Cu (6) Classify each: a (ionic, molecular, or metallic) 15. The complete mechanism for a reaction is considered to occur in two steps, one of b. d. C. e. A+B C+D slow A +2C E+F fast which is slow and the other fast: What is the rate law predicted by this mechanism? a. Rate KA[B] b. Rate =k[A][B][C]2 c. Rate K[A][C] d. Rate HA[BI[Ch e. Rate KA[B]Explanation / Answer
I am solving the first question, Q9 as per Chegg guidelines, post multiple question to get the remainng answers
Q9)
H2(g) + Br(g) ======= 2HBr(g), K = 2.0 * 10^(19)
Reversing the reaction will make the value of K' = 1/K
2HBr(g) ============ H2(g) + Br(g), K' = 5.0 * 10^(-20)
The desired reaction is 1/2 multiplied by the above reaction
HBr(g) ============ 0.5H2(g) + 0.5Br(g)
K(final) = sqrt(K') = sqrt(5.0 * 10^(-20)) = 2.2 * 10^(-10)
Option d is correct
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