6. Suppose that four applicants have applied for a position and will be intervie

Question

6. Suppose that four applicants have applied for a position and will be interviewed in random order a) How many orderings of the four applicants are possible? Now suppose that two of these applicants (A and B) are qualified for the position, and the other two applicants (C and D) are not qualified for the position. Continue to assume that the four applicants will be interviewed in random order. b) Determine the probability that neither of the first two applicants to be interviewed will be qualified. (Show your work. Express your answer as a fraction and also as a decimal with three decimal places.)

Explanation / Answer

a) Number of orders possible = 4!

= 4x3x2x1

= 24

b) P(neither of first 2 are qualified) = P(first and second are C and D) x P(third and forth are A and B)

Number of ways in which first and second can be both C and D = 2x1 x 2x1

= 4

P(neither of first 2 are qualified) = 4/24

= 0.167

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