Attempts: Keep the Highest: 6 1. Ratio of two variances test, problem 1 Aa Aa A

Question

Attempts: Keep the Highest: 6 1. Ratio of two variances test, problem 1 Aa Aa A regional fast food chain wants to ensure that their customers do not eat meat carryjing E. coll bacteria. The preventive measure is to cook the meat to the required internal temperature. Because of varying patty size and burner temperatures, meats cooked for the same length of time can have different final internal temperatures. The health department is recommending that the chain use newer, digitally controlled burners to reduce the variation in the final internal temperatures. There are two models of digitally controlled burners to choose from. The restaurant chain will choose the model with the most consistent final internal temperature of meats cooked. They sample 13 batches of meat cooked by burner model 1 and 12 batches of meat cooked by burner model 2. They found si-3.4 and s2 3.1. Is there a difference in temperature consistency? The appropriate test that the restaurant chain owner would have to perform is the What's the value of the appropriate test statistic for this test? What's the p-value for this test? Can the restaurant chain owner conclude at the 5% significance level that variances are unequal? O No O Yes For a 95% confidence interval, the lower and upper confidence limits are and Flash Player WIN 28,0,0,161 Q3 3 34.1 2004-2016 Aplia. All rights reserved D 2013 Cengage Learning except as noted. All rights reserved. Grade It Now Save & Continue

Explanation / Answer

1. F test for the rationof variance.

2.Using Minitab:

Test and CI for Two Variances

Method

Null hypothesis Sigma(1) / Sigma(2) = 1
Alternative hypothesis Sigma(1) / Sigma(2) not = 1
Significance level Alpha = 0.05

Statistics

Sample N StDev Variance
1 13 1.844 3.400
2 12 1.761 3.100

Ratio of standard deviations = 1.047
Ratio of variances = 1.097

95% Confidence Intervals

CI for
Distribution CI for StDev Variance
of Data Ratio Ratio
Normal (0.566, 1.909) (0.320, 3.643)

Tests

Test
Method DF1 DF2 Statistic P-Value
F Test (normal) 12 11 1.10 0.885

F Test statistic value is 1.10

3. P-value is 0.885

4. P-value > 0.05 we do not reject the null hypothesi. Answer is NO

5. 95% CI is (0.566, 1.909)

Hope this will be helpful. Thanks and god Bless You :-)

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