this is for single queue single server utilization rate Po is probability of ide
ID: 3045606 • Letter: T
Question
this is for single queue single server
utilization rate
Po is probability of ideal system
Wq waiting time in queue
Ws waiting time in the system
Lq number of customers in the queue
Ls number of customers in the system
then the guided questions thank you
Explanation / Answer
There are 20 tables of 6 people each which means about 120 people can sit in the restaurant. If each customer spends arounf 55 min on average, then, when the first 120 customers arrive, they will leave in the first hour.
Thus in the 3 hour dinner time window a total of 360 customers will come and leave, with a time of 15 min still remaining. The queue length is 36 people and waiting time is 15 min which is also the buffer time equal to 15 min of the 3 hour dinner time remaining.
So the arrival rate thus is approximately 120 people per hour and the service rate = 120 people / 8 waitresses = 15 people per waitress.
mu=120 people/hr
lambda=15 people/waitress
rho=lamba/mu=15/120=0.125
P(Customer will leave)=P(n>=10)=(Rho)^10=(0.125^10)=9.313226e-10
P(n<10)=0.9
1-rho^10=0.9
rho=0.631
mu=lamba/roh=15/0.631=24
serivce rate should increase from 15 people per waitresess to 24 people per waitressess
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.