Post Lab- Determine of Equilibrium Constant (CK) for a Chemical Reaction Complet

Question

Post Lab- Determine of Equilibrium Constant (CK) for a Chemical Reaction Complete the table below for the reaction (pay attention to the sig. figs. 0.2 pt. for cach blank): 3A (R) + 2B () C() 10 60 Time (s) PA (atm) 4.900 3.550 0 20 30 40 50 0.940 PB (atm) 3.000 0.960_ 0.360 Pc (atm) 0 0.750 1.210 Based on the data above, how long did it take for the reaction to establish equilibrium? (0.6 pt.) Write the equilibrium constant (K) expression for the reaction above and calculate the value of K 2 pts.) (Pa)' ( PB)

Explanation / Answer

As you have not written the data, it is dificult to say the time. Still based on the equilibrium constant, the time would be 60 seconds.

The expression for the equilibrium constant is correct. Still you must insert the data for confirmation. The expression may not match the value of equilibrium constant calculated.

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